The other night on Primo Mr Giddins did a calculation. One player hit a flush ( diamonds if I remember right ) on the Turn and Mr G said the odds , assuming his opponent had a diamond, of the river also being a diamond was 3 - 1 . But surely , given that leaves 7 diamonds unseen ( 6 out ) and 44 cards left unseen that makes roughly 1 in six = 5 -1 odds and the chance of his opponent having a better flush more like 20 - 1 . Have I missed something or is r. G. wrong.
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i can't comment on the 20-1 without knowing what the values of the diamonds were.
If there are 3 cards to make a higher flush to come that makes 3 of 44 cards which is about 14-1.