Time to pull the last Christmas Cracker

Tikay10

Really nice prize today to wrap up the Sky Poker Advent Calendar for 2018 - a £1,300 Freeroll, for which just 5 points (FIVE POINTS) are required to enter.

No doubt a few will complain that's unreasonable, but I guess that's par for the course.

Oh, & please remember to qualify well before the Freeroll starts.

MattBates

When will it appear in the lobby?
@Tikay10

Tikay10

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MattBates said:

When will it appear in the lobby?
@Tikay10

As soon as they have built it.........

Tikay10

Type your comment

MattBates said:

When will it appear in the lobby?
@Tikay10

https://www.skypoker.com/secure/poker/sky_lobby?action=go_tnmt_lobby&game_id=33193948&guid=b57411bd-b6af-4617-a6ea-fae52a9e9232

wynne1938

Got in via your link.

wynne1938

This is what the promotion says:
Earn just 5 points today and get access to an all-in Freeroll tomorrow at 3pm. The top 6

This is what is on the lobby:
£1,300 Christmas Cracker Freeroll. All players that opted in to the Christmas Cracker promo that earned at least 20 pts on Tuesday, Wednesday and Thursday will be registered.

bit of a difference!!!!!

HENDRIK62

!!!!!!!!!!

Tikay10

It was correctly set up for 5 points, but the wording was incorrect. The wording has now been corrected.

Essexphil

Tikay10 said:

It was correctly set up for 5 points, but the wording was incorrect!! The wording has now been corrected!!!!

FYP

Merry Xmas

PKRPar

wonder how many all ins required to win I'll be logging in to see anyway, could be good fun haha

GL all and merry Christmas to all players and the sky team!!

JJBinks

Great promotion, happy Christmas to players and team.

zoeboo62

thanks and merry Christmas to all

Glenelg

wonder how many all ins required to win

3000 players..6 per table all-in = 500 left? 500 ..6 per table all-in = 83 left?
83..6 all-in = 13 ......

5 or 6 all-ins? not sure tho good Q.

Someone more mathy than me will be along shortly.. Matt Bates perhaps? ;-)

MAXALLY

Glenelg said:

wonder how many all ins required to win

3000 players..6 per table all-in = 500 left? 500 ..6 per table all-in = 83 left?
83..6 all-in = 13 ......

5 or 6 all-ins? not sure tho good Q.

Someone more mathy than me will be along shortly.. Matt Bates perhaps? ;-)

Not sure about your workings, but you did get the correct answer... Matt Bates will win.

gpc70

sky have him priced up at 1/4 10s bar 1

mumsie

Glenelg said:

wonder how many all ins required to win

3000 players..6 per table all-in = 500 left? 500 ..6 per table all-in = 83 left?
83..6 all-in = 13 ......

5 or 6 all-ins? not sure tho good Q.

Someone more mathy than me will be along shortly.. Matt Bates perhaps? ;-)

This gave me the idea. 3,000 start, 5 out of 6 get eliminated(500).

2500 left, 5 out of 6 eliminated.

Leads me to the table below.

But, I dont know how to factor in tables throwing up split pots and the software will even out tables.

And Im not sure if im getting anything else wrong.

PKRPar

If there is 3000 players and 5/6 go out your down to 600 players straight away.

From 600, 5/6 is 120 players left

From 120, 5/6 is 24 players left

From 24, then final table

Boom we have a winner.

5 all ins is possible.

Tikay10

So @mumsie reckons 35 rounds, & @PKRPar thinks 5 rounds.

Bit of a difference.

Or, as I saw it typed recently, somewhat bafflingly, "bit of a difference!!!!!"

No matter, gl to all who play it.

gpc70

matt bates has shortened in price hes now 1/7 after sky bet were filled in at 1/4 by all players who no a good thing :

Allan23

I think @mumsie table shows what would happen if 1 out of 6 are knocked out on each all in on every table

SidV79

If there are 5 out of 6 players knocked out from 3000 then there will be 500 left (3000/6= 500, 500*5 = 2500= 5/6 of 3000) not 2500 or 600 so it is possible to win the tourney in 5 All-ins